Question

Kim found that 10.0 mL of a 0.50 M NaOH solution are required to completely titrate 25,0 mL of HCl solution. What is

the concentration of the HCl?

Answer 1

0.20M HCl

Step-by-step explanation:

The reaction of neutralization of NaOH with HCl is:

NaOH + HCl → H₂O + Cl⁻ + Na⁺

Where 1 mole of NaOH reacts with 1 mole of HCl.

Moles of 10.0 mL of a 0.50 M NaOH solution are:

0.0100L × (0.50moles NaOH / 1L) = 0.0050 moles of NaOH

As 1 mole of NaOH reacts with 1 mole of HCl, at equivalence point, moles of HCl are 0.0050 moles.

If volume of HCl is 25.0mL, concentration is:

0.0050 mol / 0.025L = 0.20M HCl