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Given a quadratic with one zero at 3 and a vertex at (-1,4), what is the other zero?

(Hint: plot given points on the graph and remember that quadratic graphs are symmetrical about the vertex.)

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Answer:

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function. Some say f (x) = ax2 + bx + c is "standard form", while others say that f (x) = a(x - h)2 + k is "standard form".

Explanation:

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