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Assume that all possible “ABO” blood phenotypes are present in a human population that is in Hardy-Weinberg equilibrium. If the frequency of the “A” allele is 0.24, and the frequency of the individuals in the population with blood Type O is 0.38, what is the frequency of individuals with Type B blood in the population?

User GGO
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Answer:

the frequency of individuals with Type B blood in the population is 0.1977

Step-by-step explanation:

Given:

Frequency of A allele is p = 0.24

Frequency of the individuals with blood type O is r = 0.38

Question: What is the frequency of individuals with Type B blood in the population, fB = ?

You need to apply the Hardy-Weinberg Equilibrium:

p²+q²+r²+2pq+2pr+2qr = 1

Here,

p, q and r are the frequencies of the alleles

Calculating the frequency of the allele q:


r=√(0.38) =0.6164

q = 1-p-r = 1-0.24-0.6164 = 0.1436

Frequency of individuals with type B blood:


f_(B) =q^(2) +2qr=(0.1436)^(2) +(2*0.1436*0.6164)=0.1977

User Hosar
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