A 4.00-gram sample of sodium chloride was added to a beaker containing 40.0 mL 0.033 M lead(II)
nitrate solution. Lead(II) chloride was precipitated according to the following reaction.
2NaCl(s) + Pb(NO3)2 (aq) PbCl2(s) + 2NaNO3(aq)
Calculate the mass of lead(II) chloride that can be recovered. Pb = 207; Na = 23; Cl = 35.5; N = 14;
O = 16.