Question

A gas with a temperature of 98.0 degrees Celsius has a volume of 88.0 ml. The volume is increased to 100.0 ml. What is the new temperature in degrees celsius

Answer 1

T2 = 421.76K or 148.61°C

Step-by-step explanation:

T1 = 98°C = (98 + 273.15)K = 371.15K

V1 = 88mL = 88cm³

T2 = ?

V2 = 100mL = 100cm³

1mL = 1cm³

From Charles Law,

V1 / T1 = V2 / T2

T2 = (V2 * T1) / V1

T2 = (100 * 371.15) / 88

T2 = 37115 / 88

T2 = 421.76K

T2 = 148.61°C