Question

(6 pts.) How many liters of 2.50% m/v NaCl solution will be needed in order to contain 858 g of

NaCl? Show calculation with conversion factors.

Answer 1

34.32 liters

Step-by-step explanation:

34.32 liters of 2.5% m/v NaCl solution will be needed in order to contain 858 g of NaCl.

2.5% m/v NaCl solution contains 2.5 g of NaCl in 100 mL of solution. It thus means that 100 mL has 2.5 g of NaCl.

If 100 mL solution contains 2.5 g NaCl, then, how many mL will contain 858 g?

= 100 x 858/2.5 = 34, 320 mL

Now, convert 34,320 mL to liters

1 mL = 0.001 Liters

34,320 mL = 34,320 x 0.001 L

= 34.32 liters.