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Point T is on line segment S U ‾ SU . Given T U = x − 1 , TU=x−1, S U = 3 x − 7 , SU=3x−7, and S T = x + 7 , ST=x+7, determine the numerical length of T U

User Zoos
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1 Answer

4 votes

Answer:

TU = 12

Explanation:

Given

TU = x − 1

SU = 3x − 7

ST = x + 7

TU = ?

Then we can say that

SU = ST + TU

⇒ 3x − 7 = (x + 7) + (x − 1)

⇒ 3x − 7 = 2x + 6

⇒ x = 13

Finally, we get

TU = x − 1

⇒ TU = 13 - 1

TU = 12

Therefore,

ST = x + 7 = 13 + 7 = 20

SU = 3x − 7 = 3*(13) - 7 = 32

User Kamil Szot
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