Answer:
There is enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.
Explanation:
This is a hypothesis test for the population mean.
The claim is that the true mean number of sales at location A is fewer than the true mean number of sales at location B.
Then, the null and alternative hypothesis are:

Being μ1: true mean number of sales for Location A and μ2: true mean number of sales for Location B.
The significance level is 0.01.
The sample 1 has a size n1=18 and the sample 2 has a size n2=13.
The sample 1 has a mean of 39 and a standard deviation of 8.
The sample 2 has a mean of 49 and a standard deviation of 4.
The difference between sample means is Md=-10.
The estimated standard error of the difference between means is computed using the formula:

Then, we can calculate the t-statistic as:
The degrees of freedom for this test are:
This test is a left-tailed test, with 29 degrees of freedom and t=-4.571, so the P-value for this test is calculated as (using a t-table):

As the P-value (0.00004) is smaller than the significance level (0.01), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.