Let the length of the side of the square being cut out equal x
The length of the box would be 4.5 - 2x
The width of the box would be 3 -2x
Volume = (4.5 -2x) * (3-2x) * x
Simplify to:
V = 4x^3 - 15x^2 + 13.5x
B See picture: The greatest volume would be the point of the highest curve.
x = 0.589 y = 3.565, Rounded to the nearest tenth x = 0.6
Process: entered the equation from A into Desmos. The Y value would be the volume, so found where the volume was the highest and then found the related x value.
C) X is the side length of the corner squares being cut out, which would also be the height of the box. The Y value is the volume of the box.