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The uncertainty Δp sets a lower bound on the average momentum of a particle in the nucleus. If a particle's average momentum were to fall below that point, then the uncertainty principle would be violated. Since the uncertainty principle is a fundamental law of physics, this cannot happen. Using Δp=2.1×10−20 kilogram-meters per second as the minimum momentum of a particle in the nucleus, find the minimum kinetic energy Kmin of the particle. Use m=1.7×10−27 kilograms as the mass of the particle. Note that since our calculations are so rough, this serves as the mass of a neutron or a proton.

User ATMTA
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Answer: The minimum kinetic energy Kmin is 1.3 × 10^-13 J

Explanation: Please see the attachments below

The uncertainty Δp sets a lower bound on the average momentum of a particle in the-example-1
The uncertainty Δp sets a lower bound on the average momentum of a particle in the-example-2
User Jeff Warnica
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