Question

One mole of an ideal gas was found to occupy a volume of 20.0 L a pressure of 930 MMHG and a temperature of 25°C what is the value of the gas constant in L times MMHG divided by Mol times K

Answer 1

62.4

Step-by-step explanation:

guy above me told me it was correct so i put into the box on ck-12 and it said it was correct

Answer 2

Answer : The value of the gas constant is,
`62.4\text{ mmHg.L/mol.K}`

Explanation :

Using ideal gas equation:

PV = nRT

where,

P = pressure of gas = 930 mmHg

V = volume of gas = 20.0 L

n = number of moles of gas = 1 mol

T = temperature of gas =
`25^oC=273+25=298K`

R = gas constant = ?

Now put all the given value in the above formula, we get:

`930mmHg* 20.0L=1mol* R* 298K`

`R=62.4\text{ mmHg.L/mol.K}`

Therefore, the value of the gas constant is,
`62.4\text{ mmHg.L/mol.K}`