Question

I really need help!!!

Point B has coordinates ​(3​,1​). The​ x-coordinate of point A is 0. The distance between point A and point B is 5 units. What are the possible coordinates of point​ A?
The possible coordinates of point A are

Answer 1

(0,-3) and (0,5)

Explanation:

The distance formula says that the distance^2 = {difference between x value}^2 + {difference between y value}^2.

The difference between the x values is 3, and the distance is 5, so...

5^2 = 3^2 + {difference between y value}^2

That means

25 = 9 + {difference between y value}^2

Which simplifies to

16 = {difference between y value}^2

So...

+/- 4 = {difference between y value}

1 +/-4 = -3 OR 5, so the possible coordinates of point A are:

(0,-3) and (0,5)