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If 22.6 grams of an aqueous solution of zinc nitrate, Zn(NO3)2, contains 5.08 grams of zinc nitrate, what is the percentage by mass of zinc nitrate in the solution?

____% Zn(NO3)2

User LWimsey
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2 Answers

3 votes

Answer:

Mass of Zinc Nitrate = 5.08 gm

Mass of Zinc Nitrate + water = 22.6 gm

Mass percentage of zinc Nitrate = 5.08 g x 100 % / 22.6 g = 22.47 %

Step-by-step explanation:

User Mosess
by
5.6k points
7 votes

Answer:

22.5%

Step-by-step explanation:

To find percentage by mass, you divide the mass of the solute by the mass of the solvent.

5.08 g/22.6 g = 0.2248 = 22.5%

User Brad Zacher
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5.9k points