Question

2Al + 3Cl2 → 2AlCl3

How many grams of AlCl3 are produced when 54.0 grams of Al reacts?

Answer 1

528g AlCl3

Step-by-step explanation:

***Remember that you need all the terms except "g AlCl3" to cancel out

The atomic mass of Al is about 27g and the atomic mass of AlCl3 is about 132g

`(54g Al)/(1) *(1 molAl)/(27gAl)* (2 mol AlCl3)/(1 mol Al)*(132g AlCl3)/(1 mol AlCl3)`

You need to take all the numbers and multiply/divide

528g AlCl3 should be your answer