Question

One problem with organic equations is that we tend to focus on what is happening to onemolecule at a time, we forget that there are many, many molecules undergoing COLLISIONS in thereaction. Assume you used exactly 1.5 g of 1-butanol in your reaction, calculate the number ofmol es, AND, give the number of MOLECULES of alcohol. You will need to know that a mole of asubstance is equal to Avogadro's number (6.022 x 1023) of that molecule. Give the number of molecules to3 significant figuresand do NOT USE SCIENTIFIC NOTATION, include all of the zeros in your number.After each number write down the number of zeros you included in parentheses. For example, one of youranswers was 6.022 x 1023, then you would write it as follows: 602000000000000000000000 (21 zeros).SHOW YOUR WORK and INCLUDE ALL UNITS!

Answer 1

1 2 200 000 000 000 000 000 000 (20 zeros) molecules

Step-by-step explanation:

Molar mass of 1-butanol = 74.121 g/mol

number of moles = mass given / molar mass

where mass given = 1.5 g

number of mole = 1.5 g / (74.121g/mol ) = 0.0202 moles

number of moles = number of molecules / Avogadro's constant

where Avogadro's = 6.022 × 10²³ mol⁻¹

number of moles = 6.022 × 10²³ × 0.0202 moles = 1 2 200 000 000 000 000 000 000 (20 zeros) molecules