Answer:
The impedance load that achieves maximum power transfer is 47 - j8 Ω
Step-by-step explanation:
The Power Amplifier will have output impedance Zth = 47 + j8 Ω
Voltage V = 156 at 300 Hz
Impedance of the load will be given as Zl
Zl = Zth°
Zl = 47 - j8 Ω