Answer:
Step-by-step explanation:
Let's begin by listing out the given parameters:
L = 400 mm = (400 ÷ 1000) m = 0.40 m,
W = 150 mm = (150 ÷ 1000) m = 0.15 m,
T1 = 90 °C, T2 = 14 °C
I) To calculate the heat transfer coefficient for natural convection of air over a flat plate, we use the simplified formula
hc = C * [(ΔT ÷ L)^n]
For vertical plates, C = 1.42, n = 0.25
ΔT = Tu - Tl = (90 - 14) °C = 76 °C
hc = 1.42 * [76 ÷ 0.15]^0.25
hc = 1.42 * 4.744 = 6.73648
hc = 6.74 W/m²°C
II) q = hc A (ΔT)
A = L * W = 0.4 * 0.15 = 0.06
q = 6.74 * 0.06 * 76 = 30.7344
q = 31 W