Question

How do you solve it?

Answer 1

Answer:

i: x=-2, x=1

ii: x=-1/2

Explanation:

Quadratic form:

You solve i by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

`(x+2)(x-1)=0`

"first" would be
`x*x`, which would equal
`x^(2)`

"outside" would be
`x*-1`, which would equal
`-1x, or -x`

"inside" would be
`2*x`, which would equal
`2x`

"last" would be
`2*-1`, which would equal
`-2`

Now you need to combine the terms so that they are one after the other

`x^(2)-x`
`+2x-2`

Combine like terms, and you should get:

`x^(2) +x-2`

i Solution

You need to get the variable by itself.

Subtract two from both sides

`x+2=0\\x=-2`

Add one to both sides.

`x-1=0\\x=1`

ii Solution

Add all the terms.

`x+2+x-1=0\\2x+1=0\\2x=-1\\x=-(1)/(2)`