Question

If y varies directly as x^2, and y=2 when x=1, find y when x=10

Answer 1

The value of y when x = 10 is 200

Explanation:

Here, we have y ∝ x^2 directly

⇒ y = k × x^2

where k is the constant of proportionality.

Now, let's find k from the first information set;

we can rewrite the equation as ;

k = y/x^2

k = 2/1^2 = 2/1 = 2

The value of y when x = 10 is as follows;

y = 2 × 10^2 = 2 × 100 = 200

Answer 2

200

Explanation:

Please refer to the attachment(s) for explanations