Answer:
D) The capacitor will pull the material into the space between the plates, and the potential energy stored between the plates of the capacitor will decrease by a factor of 3
Explanation:
points to note
A) inserting a material with dielectric constant of 3 between the plates means that the capacitance C will increase by 3.
B) Since the battery is disconnected, the potential difference V between plate will not remain constant.
C) increasing the capacitance reduces the potential difference across the plate, and from C = Q/V it can be seen that the charges on the plate remains constant.
From the proof in the image below, the reduction in the potential energy of the capacitor is due to the energy used by the capacitor to pull the dielectric material into the space.