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Surgery is in 4 out if every 10 hospital emergency room visits. If a large urban hospital had 840 emergency visits in the past month how many of these visits would you expect to required surgery

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Answer:

Expected number of visits to the emergency room that would require a surgery is 336.

Explanation:

Let X = number of surgery.

The odds of having a surgery in a randomly selected visit to a emergency room is 4 out of 10.

Then the probability of having a surgery in a randomly selected visit to a emergency room is:


p=(4)/(10)=0.40

In the past month a large urban hospital had 840 emergency visits.

An emergency room visit may lead to surgery or not is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 840 and p = 0.40.

The expected value of a binomial random variable is:


E(X)=np

Compute the expected number of visits that would require a surgery as follows:


E(X)=np


=840* 0.40\\=336

Thus, expected number of visits to the emergency room that would require a surgery is 336.

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