Answer:
a) 0.0537 kg, 0.877 m
b) 609 m/s²
c) 4.35 kg
Step-by-step explanation:
B = ρ(air).V(g)
Assuming g(m) is the "g" for Mars.
For a sphere, V = 4/3πR³.
Surface area of a sphere is A = 4πR²
Thus, the mass of the balloon is (4.5*10^-3 kg/m²) (4πR²)
See the attachment for the calculations