Answer:
Is halved.
Step-by-step explanation:
Hello,
In this case, by means of the Boyle's law, which allows us to understand the volume-pressure behavior as an inversely proportional relationship:
![P_1V_1=P_2V_2](https://img.qammunity.org/2021/formulas/physics/high-school/z2nkrx5zmdtkkms997yjs4edj5t3o0sadf.png)
Hence, it is given that the volume of the gas is doubled, thus:
![V_2=2V_1](https://img.qammunity.org/2021/formulas/chemistry/middle-school/1hqfl74xxoq6achi74whksmw8a0tvxwg1z.png)
In such a way, the pressure of the gas will result:
![P_2=(P_1V_1)/(V_2)=(P_1V_1)/(2V_1)\\ \\P_2=(P_1)/(2)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/3hyjlhewsicbma7nussgc45h918awdr84w.png)
Therefore, as the volume doubles, the pressure halves.
Best regards.