Answer with Explanation:
a.Intensity of radiation is directly proportional to the frequency of radiation
When the intensity of radiation increases then the frequency of radiation increases and therefore, the number of photo-electrons emitted by the metal increases.
b.When all of the wavelength in the radiation are increased by the same amount
We know that
![f=(v)/(\lambda)](https://img.qammunity.org/2021/formulas/physics/college/waj3zww8wgvsyv90ar99zdka02wvpo8fr6.png)
Frequency is inversely proportional to the wavelength.
Therefore, the frequency decrease .
When the frequency decreases then the number of photo-electrons emitted by the metal decrease.
c.When the work function of the metal is increased then the gain of kinetic energy decreases .
When energy decreases then the number of photo-electrons emitted by the metal decreases.