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The figure below shows the first floor plan of a museum. The plan is drawn to scale with 1 centimeter : 0.8 meters. What is the area of the actual museum’s first floor?

User RBA
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1 Answer

4 votes

Answer:

The total area ( A ) of the first floor is 375.2 m^2

Explanation:

Solution:-

- The architect used a scale of:

1 cm ( drawing ) -----> 0.8 m ( actual ).

- The drawing of the first floor plan of the museum can be broken down into 3 section: A triangle, rectangle and a semi-circle.

- We will determine the area of each section in actual values using the scale of the drawing.

Triangle:-

- The drawing shows a triangle with scale height " hs " = 7 cm and scale base length " bs " = 18 cm.

- First step is to determine the equivalent actual dimension of actual height "ha" and actual base length " ba " using the scale: So,

1 cm ( drawing ) -----> 0.8 m ( actual )

hs = 7 cm -------------> ha

========================================

ha = 7*0.8 , ha = 5.6 m

========================================

1 cm ( drawing ) -----> 0.8 m ( actual )

bs = 18 cm -------------> ba

========================================

ba = 18*0.8 , ba = 14.4 m

========================================

- The area of the triangle is given by the formula:

A1 = 0.5*ba*ha

A1 = 0.5*14.4*5.6

A1 = 40.32 m^2

Rectangle:-

- The drawing shows a rectangle with scale length " ls " = 22 cm and scale width " ws " = 18 cm.

- First step is to determine the equivalent actual dimension of actual length "la" and actual base width " wa " using the scale: So,

1 cm ( drawing ) -----> 0.8 m ( actual )

ls = 22 cm -------------> la

========================================

la = 22*0.8 , la = 17.6 m

========================================

1 cm ( drawing ) -----> 0.8 m ( actual )

ws = 18 cm -------------> wa

========================================

wa = 18*0.8 , wa = 14.4 m

========================================

- The area of the rectangle is given by the formula:

A2 = la*wa

A2 = 14.4*17.6

A2 = 253.44 m^2

Semi-circle:-

- The drawing shows a semicircle with scale diameter " ds " = 18 cm

- First step is to determine the equivalent actual diameter of semicircle "da": So,

1 cm ( drawing ) -----> 0.8 m ( actual )

ds = 18 cm -------------> da

========================================

da = 18*0.8 , da = 14.4 m

========================================

- The area of the semicircle is given by the formula:

A3 = π*da^2 / 8

A3 = π*(14.4)^2 / 8

A3 = 81.43008 m^2

- The total area of the first floor in actual is the sum of area of each sections:

A = A1 + A2 + A3

A = 40.32 + 253.44 + 81.43008

A = 375.2 m^2

Answer: The total area ( A ) of the first floor is 375.2 m^2

User Kane Chew
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