Question

In humans curly hair (C) is dominant to straight hair (c), and freckles (F) is dominant to not having freckles. A man heterozygous for curly hair and who has no freckles marries a woman with straight hair and who is heterozygous for freckles. What is the probability of having a child with this genotype: CcFf

Answer 1

freckles with straight hair

Step-by-step explanation:

Answer 2

Probability of having a child with this genotype: CcFf is
`(1)/(4)`

Step-by-step explanation:

Given -

Curly hair (C) is dominant to straight hair (c)

and

Freckles (F) is dominant to not having freckles (f)

Genotype of man heterozygous for curly hair and no freckles is Ccff

Genotype of woman with straight hair and heterozygous condition for freckles is ccFf

The cross is between Ccff and ccFf

The following offspring would be produced

Ccff and ccFf

Cf Cf cf cf

cF CcFf CcFf ccFf ccFf

cF CcFf CcFf ccFf ccFf

cf Ccff Ccff ccff ccff

cf Ccff Ccff ccff ccff

Genotype –

CcFf – 4 in number

ccFf - 4 in number

Ccff - 4 in number

ccff - 4 in number

Phenotype

CcFf – heterozygous for both the curly hairs and freckles

ccFf – straight hairs with heterozygous freckle condition

Ccff – Heterozygous curly hair with no freckles

ccff – staright hairs with no freckels

probability of having a child with this genotype: CcFf is

`(4)/(16) \\(1)/(4)`