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How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?

User Tcables
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1 Answer

4 votes

Answer:

550 J

Step-by-step explanation:

The formula for the amount of heat (q) released by the copper is

q = mCΔT

Data:

n = 0.762 mol

C = 0.386 J°C⁻¹g⁻¹

T_i = 81.6 °C

T_f = 52.2 °C

Calculations:

(a) Mass of copper

\text{Mass} = \text{0.762 mol} \times \dfrac{\text{63.55 g}}{\text{1 mol}} = \text{48.43 g}

(b) ΔT

ΔT = 81.6 °C - 52.2 °C = 29.4 °C

(c) q

q = mCΔT = 48.43 g × 0.386 J·°C⁻¹g⁻¹ × 29.4 °C = 550 J

The amount of heat released by the copper is 550 J.

User Mkso
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