Answer:
Check the explanation
Step-by-step explanation:
The potential of a cell can be calculated as:
cell = E . cathode - E
So, incase we will be needing a potential of at least 1.10 V and there is a cathodic potential of 1.03 V, we will therefore be needing an anodic potential with a value of -0.07 V or lower (that is, more negative). So yes, there is a minimum and it should be - 0.07 V.
so far the cell has to be of AT LEAST 1.10 V and an upper limit is absent, then the reduction potential at the anode has no maximum value (again, we will have to take into account that it has to be more negative than -0.07 V).
A half-reaction that complies and corrolates with this condition is the following (written as an oxidation, which is how it actually happens at the anode):
Pb(s) --> Pb2+(aq) + 2 e-