How many 4 digit codes are possible if the first digit cannot be 0 and digits can be repeated?

asked Feb 28, 2021 50.9k views

2 votes

8.1k points

Please log in or register to add a comment.

5 votes

Answer: 9,000

Step-by-step explanation: there are 9 number options for the first digit and 10 for the other 3, so 9x10x10x10=9000

Jose Ibanez answered Mar 6, 2021

8.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.2m questions

11.8m answers