Question

A gas has a pressure of 50.0 mmHG at a temperature of 540 K. What will be the temperature if the pressure goes down to 3 mmHg?

Answer 1

`T_2=32.4K`

Step-by-step explanation:

Hello,

In this case, we use the Gay-Lussac's law which allows us to understand the pressure-temperature relationship as a directly proportional relationship:

`(P_1)/(T_1)=(P_2)/(T_2)`

Hence, we solve for the final temperature as shown below:

`T_2=(T_1P_2)/(P_1)= (540K*3mmHg)/(50.0mmHg) \\\\T_2=32.4K`

Best regards.

Answer 2

32.4 K

Step-by-step explanation:

Initial pressure P1= 50.0mmHg

Initial temperature T1= 540K

Final temperature T2=????

Final pressure P2= 3 mmHg

From

P1/T1= P2/T2

P1T2= P2T1

T2= P2T1/P1

T2= 3×540/50.0= 1620/50.0

T2= 32.4 K