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A scalpel made of surgical stainless steel is sterilized by heating in a flame and then quenching in 175 g of ethyl alcohol. The

alcohol is initially room temperature, 23.7°C, warms to 38.6°C. The specific heat capacity of ethyl alcohol is 2.4 J/(g'K) Assuming
there is no heat lost to the surroundings, calculate the heat released by the alcohol.
-6300 J
-3600 J
6200 J
7800 J

User Huxley
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4.6k points

1 Answer

4 votes

Answer:

-6300J

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance per unit of mass could be written as:

Q = -m×C×ΔT

Where Q is heat, m is mass of substance, C is specific capacity and ΔT is change in temperature.

Replacing:

Q = -175g × 2.4J/gK × (38.6°C-23.7°C)

Q = -6258J ≡ -6300J

User Tamas
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5.3k points