Answer : The temperature (Celsius) if they each shrink to a volume of 2.0 liters is,
![93.1^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/gd3oo9vq1s9rsm19l1bcmva1de39wjjy6e.png)
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![(P_1V_1)/(T_1)=(P_2V_2)/(T_2)](https://img.qammunity.org/2021/formulas/physics/high-school/xkw5w11w5j6h3n0i0p5108jnbt1i78v4rv.png)
where,
= initial pressure of gas = 1.00 atm
= final pressure of gas = 0.77 atm
= initial volume of gas = 2.5 L
= final volume of gas = 2.0 L
= initial temperature of gas =
![19^oC=273+19=292K](https://img.qammunity.org/2021/formulas/chemistry/high-school/ve1i9ugu9hlhm9o2cq0gc13w9vm8503td3.png)
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
![(1.00atm* 2.5L)/(292K)=(0.77atm* 2.0L)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/r4oym5d4j4mnw2vn29npz9xklzsrru15kb.png)
![T_2=179.9K=273-179.9=93.1^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/zcryuo8b1nf9d28v4w9314rz2qbhol0z33.png)
Therefore, the temperature (Celsius) if they each shrink to a volume of 2.0 liters is,
![93.1^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/gd3oo9vq1s9rsm19l1bcmva1de39wjjy6e.png)