Question

When 92.6 g K2CO3 is dissolved in 429 mL of solution, the molarity of the solution is:

0.287 M
1.56 M
1.38 M
0.670 M
6.40 M

Answer 1

To calculate the molarity of the solution, divide the moles of solute by the volume of the solution. In this case, the molarity is 1.56 M.

Step-by-step explanation:

To calculate the molarity of a solution, we need to divide the number of moles of solute by the volume of the solution in liters.

In this case, we are given that there are 92.6 g of K2CO3 as the solute and the solution has a volume of 429 mL (0.429 L).

First, we need to convert the mass of K2CO3 into moles by dividing by its molar mass. The molar mass of K2CO3 is 138.2 g/mol.

Moles of K2CO3 = 92.6 g / 138.2 g/mol = 0.670 mol

Now, we can calculate the molarity:

Molarity = Moles / Volume = 0.670 mol / 0.429 L = 1.56 M