Question

On a trip, you notice that a 2.27 kgbag of ice lasts an average of 1 day in your cooler. What is the average power absorbed by the ice if the ice starts at 0∘C and completely melts to liquid water at 0∘C in exactly 1 day? The latent heat of fusion for water is 334 kJ/kg.

Answer 1

Answer:8.77 W

Step-by-step explanation:

Given

mass of ice
`m=2.27\ kg`

Latent heat of fusion
`L=334\ KJ/kg`

1 day is equivalent to 24 hr

`24\approx 8.64* 10^4\ s`

Heat required to melt ice completely

`Q=mL`

`Q=2.27* 334=758.18\ kJ`

Average power absorbed by ice
`P`

`P_(avg)=(Q)/(\Delta t)`

`P_(avg)=(758.18)/(8.64* 10^4)`

`P_(avg)=8.77\ W`