Answer:
The number of different committees that are possible is 200.
Explanation:
Combinations is a mathematical procedure to determine the number of ways to select k items from n distinct items.
![{n\choose k}=(n!)/(k!(n-k)!)](https://img.qammunity.org/2021/formulas/mathematics/college/y5kg37io9k9rsp83yxi4epm2na4n54n2j8.png)
The group consists of 6 juniors and 5 sophomores.
The committee to be formed must consist of 3 juniors and 3 sophomores.
Compute the number of ways to select 3 juniors from 6 as follows:
![n (3\ juniors)={6\choose 3}=(6!)/(3!(6-3)!)=(6!)/(3!*3!)=(6* 5* 4*3!)/(3!* 3!)=20](https://img.qammunity.org/2021/formulas/mathematics/high-school/w6ua66w3bhnly71i0k084t8mkkl9lxe477.png)
Compute the number of ways to select 3 sophomores from 5 as follows:
![n (3\ sophomores)={5\choose 3}=(5!)/(3!(5-3)!)=(5!)/(3!*2!)=(5* 4*3!)/(3!* 2!)=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/659uzvy453ti29m3zvoagzq5y55jezi5qk.png)
Compute the total number of different committees possible as follows:
Total number of committees possible = n (3 juniors) × n (3 sophomores)
![={6\choose 3}* {5\choose 3}\\=20* 10\\=200](https://img.qammunity.org/2021/formulas/mathematics/high-school/xaj30lw25cn4531cefynkews47pmiszwrq.png)
Thus, the number of different committees that are possible is 200.