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At STP, a sample of gas occupies 0.225 L. Calculate the volume of this gas at a pressure of 2.7 atm and a temperature of 320 K.

User Waveter
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1 Answer

3 votes

Answer:

This new temperature is 97.7 mL

Step-by-step explanation:

Step 1: Data given

Volume = 0.225 L

STP = 1 atm and 273 K

Pressure = 2.7 atm

Temperature = 320 K

Step 2: Calculate new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the pressure at STP = 1 atm

⇒with V1 = the volume = 0.225 L

⇒with T1 = the temperature at STP = 273 K

⇒with P2 = the new pressure = 2.7 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the new temperature = 320 K

(1atm *0.225 L)/273 K = (2.7 atm * V2) /320 K

8.24 * 10^-4 = 2.7 * V2 / 320K

2.7V2 = 0.264

V2 = 0.0977 L = 97.7 mL

This new temperature is 97.7 mL

User Rowland Shaw
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