Question

a piece of pure silver in the shape of a rectangle pyramid with the dimesions shown has a mass of 19.9 grams. what is the density of silver? round to the nearest tenth

Answer 1

density of the metal silver = 6.6
`(g)/(cm^(3) )`

Explanation:

Piece of pure silver is in the shape a rectangular pyramid.

Volume of a rectangular pyramid =
`(1)/(3)(\text{Area of the rectangular base})* (\text{height})`

=
`(1)/(3)(3* 2)(1.5)`

= 3 cm³

Formula for the density is,

Density =
`\frac{\text{Mass}}{\text{Volume}}`

Density of silver =
`\frac{\text{Mass of the silver piece}}{\text{Volume of the silver piece}}`

=
`(19.9)/(3)`

= 6.63

≈ 6.6
`(g)/(cm^(3) )`

Therefore, density of the metal silver = 6.6
`(g)/(cm^(3) )`