Question

A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.31 M Pb(NO3)2 solution that is needed.

Answer 1

Answer : The volume, in milliliters, of the 0.31 M
`Pb(NO_3)_2` solution that needed is, 50.9 mL

Explanation :

Formula used :

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the initial molarity and volume of dilute
`Pb(NO_3)_2`.

`M_2\text{ and }V_2` are the final molarity and volume of
`Pb(NO_3)_2`.

We are given:

`M_1=0.31M\\V_1=?\\M_2=0.19M\\V_2=83.0mL`

Putting values in above equation, we get:

`0.31M* V_1=0.19M* 83.0mL\\\\V_1=50.9mL`

Hence, the volume, in milliliters, of the 0.31 M
`Pb(NO_3)_2` solution that needed is, 50.9 mL