Answer:
![CL_(max) = 2.182](https://img.qammunity.org/2021/formulas/engineering/college/gp15m7c729s13b69ril55n300iavarrkg8.png)
Step-by-step explanation:
Given that;
weight of the airplane = 49,000 lbs
wing area
= 529 ft²
Thrust = 17000 lbs
Length of the catapult = 400 ft
Initial speed
= 0
Final speed
![v_2 = 140 \ knots](https://img.qammunity.org/2021/formulas/engineering/college/dbmsq82xbrlu459wdz207ouwlryogf45qm.png)
density
= 0.002376 slugs/ft³
To find the
; we have:
=
![(140)/(1.25)](https://img.qammunity.org/2021/formulas/engineering/college/ummmv41ohqwubg79r9j5anhsfescqzkowh.png)
= 112 knots
= 112 × 1.6878 ft/s
= 189.0336 ft/s
Weight W =
![(1)/(2) \rho *V^2_(stall) *S_w*CL_(max)](https://img.qammunity.org/2021/formulas/engineering/college/d8hv6c41md2iy4drhwei6g5k0yq7xcqb7e.png)
![CL_(max) = (2 W)/(\rho * V^2_(stall)*S_w)](https://img.qammunity.org/2021/formulas/engineering/college/vq6ckcw4v8lt2j2809ecun7oe7x3ndyjfy.png)
![CL_(max) = (2 * 49000)/(0.002376 * 189.0336^2*529)](https://img.qammunity.org/2021/formulas/engineering/college/xcuqrl2c342hjr6xji0hz3dj0p50yw8a9j.png)
![CL_(max) = 2.182](https://img.qammunity.org/2021/formulas/engineering/college/gp15m7c729s13b69ril55n300iavarrkg8.png)