Answer:
The list that represents the sample space for two mornings at the stop light is:
(R,R)
(R,G)
(R,Y)
(Y,R)
(Y,G)
(Y,Y)
(G,R)
(G,G)
(G,Y)
11.11% probability of the light being red on two mornings.
Explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem:
We build the sample space similar to a truth table.
I am going to say that R is red, Y is yellow and G is green
The sample space for two mornings is:
All the possible outcomes, that is:
(R,R)
(R,G)
(R,Y)
(Y,R)
(Y,G)
(Y,Y)
(G,R)
(G,G)
(G,Y)
The size of the sample space is 9(9 total outcomes). Only one outcome is desired, (R, R). So
p = 1/9 = 0.1111
11.11% probability of the light being red on two mornings.