39.2k views
1 vote
To evaluate the following​ integral, carry out these steps.

a. Sketch the original region of integration R in the​ xy-plane and the new region S in the​ uv-plane using the given change of variables.
b. Find the limits of integration for the new integral with respect to u and v.
c. Compute the Jacobian.
d. Change variables and evaluate the new integral.

Modifying Below Integral from nothing to nothing Integral from nothing to nothing With Upper R∫∫Rx squared StartRoot x plus 2y EndRoot 2x+2y ​dA, where Upper R equals StartSet (x comma y ): 0 less than or equals x less than or equals 2 comma negative StartFraction x Over 2 EndFraction less than or equals y less than or equals 1 minus x EndSetR=(x,y): 0≤x≤2, − x 2≤y≤1−x​; use x equals 2 ux=2u​, y equals v minus uy=v−u.

1 Answer

2 votes

Answer:

The integral part of your question is not comprehensive enough. The answer provided below is for the integral;


\int\limitsa_R \int\limitsa {x^(2) \sqrt{(x^(2)+2y)} dA

Where:

R={(xy) 0≤x≤2, − x 2≤y≤1−x}

Step-by-step explanation:

See the attached file for the calculations.

To evaluate the following​ integral, carry out these steps. a. Sketch the original-example-1
To evaluate the following​ integral, carry out these steps. a. Sketch the original-example-2
User Danilo Gomes
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories