Answer:
1. 0.662 M
2. 2.294 M
3. 0.357 M
Step-by-step explanation:
The Molarity of a compound is simply defined as the mole of compound per unit litre of the solution. It can be obtained mathematically by the following equation:
Molarity = mole /Volume
With the equation above, let us calculate the molarity for the question given above.
1. Mole of CuSO4 = 0.49 mol Volume = 0.74 L.
Molarity of CuSO4 =?
Molarity = mole /Volume
Molarity of CuSO4 = 0.49/0.74
Molarity of CuSO4 = 0.662 M
2. Mole of Co(NO3)2 = 0.78 mol Volume = 0.34 L.
Molarity of Co(NO3)2 =?
Molarity = mole /Volume
Molarity of Co(NO3)2 = 0.78/0.34
Molarity of Co(NO3)2 = 2.294 M
3. Mole of K2Cr2O4 = 0.30 mol Volume = 0.84L.
Molarity of K2Cr2O4 =?
Molarity = mole /Volume
Molarity of K2Cr2O4 = 0.30/0.84
Molarity of K2Cr2O4 = 0.357 M