Question

4 chairs and 3 tables together cost ₨ . 2100 and 5 chairs and 2 tables cost Rs.1750. Find the cost of 1 chair and 1 table while solving by elimination method.

Answer 1

Cost of one chair = Rs . 150

Cost of one table = Rs. 500

Explanation:

Let number of chairs denote x and no of tables denote y

4x + 3y = 2100 --------------------(i)

5x +2y = 1750 ------------------(ii)

Multiply equation (i) by 2 and (ii) by (-3) and now y will be eliminated.

(i)*2 8x + 6y = 4200

(ii)*(-3) -15x - 6y = - 5250 {Now, add}

- 7x = - 1050

x = -1050/-7

x = Rs. 150

Plug in the value of x inn equation (i)

4*150 + 3y = 2100

600 + 3y = 2100

3y = 2100 - 600

3y = 1500

y= 1500/3

y =Rs 500