Question

A sample of gas occupies 250 mL at STP. What is the temperature if the gas expands to 1500 mL at a pressure of 0.500 atm? *

Answer 1

819 K

Step-by-step explanation:

Given data

• Initial pressure (P₁): 1 atm (standard pressure)

• Initial volume (V₁): 250 mL

• Initial temperature (T₁): 273.15 K (standard temperature)

• Final pressure (P₂): 0.500 atm

• Final volume (V₂): 1500 mL

• Final temperature (T₂): ?

We can find the final temperature using the combined gas law.

`(P_1 * V_1 )/(T_1) = (P_2 * V_2 )/(T_2)\\T_2 = (P_2 * V_2 * T_1 )/(P_1 * V_1) = (0.500atm * 1500mL * 273.15K )/(1atm * 250mL)=819K`