Question

At STP (101.3 kPa, 0 degrees Celsius)one mole of Ar gas was collected and was found to occupy a volume of 22.4 L. What is the value of the gas constant in L*kPa/mol*K?

Answer 1

8.31

Step-by-step explanation:

CK-12

Answer 2

`R_(u) = 8.307\,(kPa\cdot L)/(mol\cdot K)`

Step-by-step explanation:

Let assume that Argon behaves ideally. The equation of state for an ideal state is:

`P\cdot V = n \cdot R_(u)\cdot T`

The gas constant is:

`R_(u) = (P\cdot V)/(n\cdot T)`

`R_(u) = ((101.3\,kPa)\cdot (22.4\,L))/((1\,mol)\cdot (273.15\,K))`

`R_(u) = 8.307\,(kPa\cdot L)/(mol\cdot K)`