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How many moles of H2s are produced when 2.25 moles Hcl react with excess zns

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Answer:

1.125 moles of H2S

Step-by-step explanation:

From 2HCl(aq) + ZnS(s) ---------> H2S (g) + ZnCl2 (aq)

From the reaction equation;

2 moles of HCl produces 1 mole of H2S

Therefore 2.25 moles of HCl will produce 2.25 ×1/2 = 1.125 moles of H2S

Recall that it was explicitly stated in the question that ZnS is the reactant in excess. This implies that HCl is the limiting reactant and controls the amount of product obtained.

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