Question

Find the perimeter of triangle ABC.

Answer 1

21.79 units

Explanation:

We have to use the distance formula, which says that for two points (x_1, y_1) and (x_2, y_2), the distance between them is:
`√((x_1-x_2)^2+(y_1-y_2)^2)`

First up is (2, 2) and (6, 6):
`√((2-6)^2+(2-6)^2)=√((-4)^2+(-4)^2)=√(16+16)=√(32) =4√(2)` ≈ 5.66

Next is (6, 6) and (7, -3):

`√((7-6)^2+(-3-6)^2)=√((1)^2+(-9)^2)=√(1+81)=√(82)` ≈ 9.06

Finally is (2, 2) and (7, -3):

`√((2-7)^2+(2-(-3))^2)=√((-5)^2+(5)^2)=√(25+25)=√(50) =5√(2)` ≈ 7.07

Add these up:

5.66 + 9.06 + 7.07 = 21.79 units

Hope this helps!