Question

A balloon is inflated with 0.1247mol of Helium gas to a pressure of 1.26atm. If the volume 1.25L, what must the temperature be in Kelvin?

Answer 1

`T = 154.028\,K`

Step-by-step explanation:

Let consider that helium behaves ideally. The equation of state of the ideal gas is:

`P \cdot V = n \cdot R_(u)\cdot T`

The temperature is cleared in the expression presented above:

`T = (P\cdot V)/(R_(u)\cdot n)`

The temperature of the helium inside the balloon is:

`T = ((1.26\,atm)\cdot (1.25\,L))/(\left(0.082\,(atm\cdot L)/(mol\cdot K) \right)\cdot (0.1247\,mol))`

`T = 154.028\,K`