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Determine the slope of the tangent to the graph of y=-x^3+2.5x^2-3x+1 at the point where x=2
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5 votes
Determine the slope of the tangent to the graph of y=-x^3+2.5x^2-3x+1 at the point where x=2

User Kevindra
by
4.2k points

1 Answer

6 votes

Answer:

-5

Explanation:


(dy)/(dx) =-3x^2+5x-3\\x=2\\(dy)/(dx) =-3(2)^2+5(2)-3=-12+10-3=-5

User Leastprivilege
by
5.3k points
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