121k views
4 votes
A fair, 12-sided die has numbers on each of its faces. There are three faces with a 1, three faces with a 2, one face with a 3, four faces with a 4, and one face with a 5.

What is the expected value when rolling this die?

User Truefalse
by
8.2k points

1 Answer

5 votes

Answer:

2.75

Explanation:

Let's start by making a frequency table. If there is one face, you have a 1/12 chance of getting the value--that's what the "frequency" column means.

Face Frequency

1 3/12

2 3/12

3 1/12

4 4/12

5 1/12

Now to get E(X) we need to multiply each face by the frequency of it occuring and add all these together:

E(X) = 1(3/12) + 2(3/12) + 3(1/12) + 4(4/12) + 5(1/12)

= 2.75

User MerklT
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories